Q=150(10x.67^2+7)

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Solution for Q=150(10x.67^2+7) equation: 



=150(10Q.67^2+7)

We move all terms to the left:

-(150(10Q.67^2+7))=0



We calculate terms in parentheses: -(150(10Q.67^2+7)), so:

150(10Q.67^2+7)

We multiply parentheses

1500Q+1050

Back to the equation:

-(1500Q+1050)



We get rid of parentheses

-1500Q-1050=0

We move all terms containing Q to the left, all other terms to the right

-1500Q=1050

Q=1050/-1500

Q=-7/10

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